Ratio, Rate And Speed
In this chapter, we will be discussing the below mentioned topics in detail:
- Finding and simplifying ratios of quantities with units
- Finding unknowns in a ratio
- Problems involving ratios of two quantities
- Problems involving ratios of three quantities
A) Finding Ratio
A ratio compares two quantities of the same kind that either have no units or are measured in the same units.
The ratio a:b, where a and b are positive integers, has no units.
Let’s understand this with the help of some examples:
Question 1:
A map has a scale where 1cm represents 1km. Express the map scale as a ratio.
Solution:
1cm:1km1cm:1000m(Converting kilometres into metres)1cm:100000cm(Converting metres into centimetres)1:100000
Hence, the ratio would be 1:100000.
B) Equivalent Ratio
Equivalent ratios are ratios that remain the same when compared.
Let’s understand this with the help of some examples:
Question 2:
Without using a calculator, simplify each of the following ratios.
- 38:334
- 0.24:0.08
Solution:
38:33438:15438×8:154×83:3033:3031:10
0.24:0.080.24×100:0.08×10024:8248:883:1
C) Finding unknowns in a ratio
Let’s understand this with the help of some examples:
Question 3:
- Given that 3x−5:8=x:2, find the value of x.
- Given that 5a9=2b15, find the ratio of a:b.
Solutions:
3x−58=x22(3x–5)=8x6x–10=8x–10=2xx=–5
5a9=2b155a×15=9×2b75a=18bab=1875=625a:b=6:25
D) Problems involving ratios of two quantities
Let’s understand this with the help of some examples:
Question 4:
The ratio of the number of children to the number of adults at an event is 3:7.If there are 32 fewer children than adults, calculate the total number of people at the event.
Solution:
Let the number of children =3x
Then, number of adults =7x
7x–3x=324x=32x=8
Total number of people
=3x+7x=10x=10×8=80
E) Problems involving ratios of three quantities
Let’s understand this with the help of some examples:
Question 5:
Patrick, Rachel and Quincy shared a sum of money in the ratio 3:4:7. If Patrick and Quincy each receive $10 from Rachel, the ratio becomes 7:6:15. Calculate the total amount of money all three of them had at first.
Solution:
Let Patrick have $3x at first.
Then Rachel had $4x and Quincy had $7x at first.
P:Q:RBefore3x:4x:7xAfter3x+10:4x–20:7x+15
3x+104x−20=766(3x+10)=7(4x–20)18x+60=28x–140200=10xx=20
Total money at first
=14x=14(20)=$280