chevron icon chevron icon chevron icon

Length, Mass And Volume

In this article, the learning objectives are: 

  1. Reading scale involving length
  2. Reading scale involving mass
  3. Reading scale involving volume

 

Measuring Length

To measure the length of an object, we will usually use a ruler. In most occasions, we will place the object at the starting point and see where it ends, and that would be the length of the object. 

It is also possible to start measuring from any point. In these cases, we will have to do subtraction to find the length of the object.

 

Question 1: 

Look at the diagram below.

The length of the paper clip is __________ \(\text{ cm }\).

 

Solution: 

Length of the paper clip 

\(=\) Length at end point - Length at start point

\(= 11 \text{ cm } - 4 \text{ cm }\)

\(= 7 \text{ cm }\)

Answer:

\(7 \text{ cm }\)


 

Question 2: 

Look at the diagram below.

The pencil is __________ \(\text{ cm }\) longer than the fork.

 

Solution: 

Length of the pencil 

\(=\) Length at end point \(-\) Length at start point

\(= 11 \text{ cm } - 1 \text{ cm }\)

\(= 10 \text{ cm }\)

 

Length of the fork

\(=\) Length at end point \(-\) Length at start point

\(= 6 \text{ cm } - 0 \text{ cm }\)

\(= 6 \text{ cm }\)

 

Difference in length between the pencil and the fork

\(= 10 \text{ cm } - 6 \text{ cm }\)

\(= 4 \text{ cm }\)

Answer:

\(4 \text{ cm }\)


 

Question 3:

Look at the diagram below.

The total length of Sticks A, B and C is __________ \(\text{ cm }\).

 

  1. 9
  2. 12
  3. 15
  4. 20

 

Solution: 

Length of Stick A

\(=\) Length at end point \(-\) Length at start point

\(= 9 \text{ cm } - 1 \text{ cm }\)

\(= 8 \text{ cm }\)

 

Length of Stick B

= Length at end point \(-\) Length at start point

\(= 7 \text{ cm } - 0 \text{ cm }\)

\(= 7 \text{ cm }\)

 

Length of Stick C

\(=\) Length at end point \(-\) Length at start point

\(= 8 \text{ cm } - 3 \text{ cm }\)

\(= 5 \text{ cm }\)

 

Total length of Sticks A, B and C

\(= 8 \text{ cm } + 7 \text{ cm } + 5 \text{ cm }\)

\(= 20 \text{ cm }\)

Answer:

(4) \(20 \text{ cm }\)

 

 

Question 4: 

Look at the diagram below.

What is the height of the bookshelf?

 

  1. 200\(\text{ cm }\)
  2. 210\(\text{ cm }\)
  3. 220\(\text{ cm }\)
  4. 240\(\text{ cm }\)

 

Solution: 

\(1 \text{ m }= 100 \text{ cm }\)

Length represented by 5 intervals \(= 100 \text{ cm }\)

Length represented by 1 interval 

\(= 100\text{ cm } \div 5\)

\(= 20 \text{ cm }\)

 

The height of the cupboard is 1 interval above \(2 \text{ m}\)

Height of the bookshelf 

\(= 2 \text{ m } 20 \text{ cm }\)

\(= 220 \text{ cm }\)

Answer:

(3) \(220\text{ cm }\)


 

Measuring Mass

To measure the mass of an object, we usually use a weighing scale. To find the mass of the object, we have to first find the value of each interval. From there, we will be able to determine the mass of the object by looking at which interval the arrow is pointing to.

 

Question 1: 

Look at the diagram below.

The mass of the bag of rice is __________.

 

Solution: 

Mass represented by 10 intervals \(= 1000 \text{ g }\)

Mass represented by 1 interval 

\(= 1000 \text{ g } \div 10 \)

\(= 100 \text{ g }\)

 

The mass of the bag of rice is 4 intervals after \(4 \text{ kg }\)

Mass of the bag of rice \(= 4 \text{ kg } 400 \text{ g }\)

Answer:

\(4 \text{ kg } 400 \text{ g } \text{or }4400\text{g}\) .


 

Question 2: 

Look at the diagram below.

What is the mass of the grapes?

 

  1. 356\(\text{ g }\)
  2. 360\(\text{ g }\)
  3. 600\(\text{ g }\)
  4. 3600\(\text{ kg }\)

 

Solution: 

Mass represented by 10 intervals \(= 100 \text{ g }\)

Mass represented by 1 interval 

\(= 100 \text{ g } \div 10 \)

\(= 10 \text{ g }\)

 

The mass of the grapes is 6 intervals after \(300 \text{ g }\)

Mass of grapes \( = 360 \text{ g }\)

Answer:

(2) \(360\text{ g }\)


 

Question 3: 

Look at the diagram below.

The total mass of the grapes and bananas is __________.

 

Solution: 

Mass represented by 10 intervals \(= 100 \text{ g }\)

Mass represented by 1 interval 

\(= 100 \text{ g} \div 10 \)

\(= 10 \text{ g }\)

 

The mass of grapes is 5 intervals after \(300 \text{ g }\)

Mass of the grapes \(= 350 \text{ g } \)

 

The mass of bananas is 3 intervals after \(200 \text{ g }\)

Mass of the bananas \(= 230\text{ g}\)

 

Total mass of the grapes and bananas 

\(= 350 \text{ g } + 230 \text{ g }\)

\(= 580 \text{ g }\)

Answer:

\(580 \text{ g }\)


 

Question 4: 

Look at the diagram below.

The mass of the big ball is \(39 \text{ g }\)

What is the mass of the small ball?

 

  1. 29\(\text{ g }\)
  2. 30\(\text{ g }\)
  3. 31\(\text{ g }\)
  4. 32\(\text{ g }\)

 

Solution: 

Mass represented by 10 intervals \(= 20 \text{ g }\)

Mass represented by 1 interval 

\(= 20 \text{ g} \div 10 \)

\(= 2\text{ g }\)

 

The total mass of the big ball and the small ball is 4 intervals after \(60 \text{ g }\)

Total mass of the big ball and small ball \(= 68 \text{ g }\)

Mass of small ball 

\(= 68 \text{ g} - 39 \text{ g } \)

\(= 29\text{ g }\)

Answer:

(1) \(29 \text{ g }\)


 

Question 5: 

Look at the diagram below.

4 identical apples are placed on a weighing scale.

The mass of 1 apple is __________. 

 

Solution: 

Mass represented by 10 intervals \(= 2000 \text{ g }\)

Mass represented by 1 interval 

\(= 2000\text{ g} \div 10 \)

\(= 200\text{ g }\)

 

The mass of 4 apples is 2 intervals after \(2 \text{ kg}\)

Mass of 4 apples \(= 2400\text{ g }\)

Mass of 1 apple 

\(= 2400 \text{ g} \div 4\)

\(= 600 \text{ g } \)

The mass of 1 apple is \(600\text{ g }\).

Answer:

\( 600\text{ g }\)


 

Question 6: 

Look at the diagram below.

The weighing scale shows the mass of a basket and 5 identical apples. 

The mass of the basket is \(150\text{ g }\)

What is the mass of 1 apple?

 

  1. 50\(\text{ g }\)
  2. 70\(\text{ g }\)
  3. 350\(\text{ g }\)
  4. 500\(\text{ g }\)

 

Solution: 

Mass of the basket and 5 apples \(= 500 \text{ g }\)

Mass of 5 apples 

\(= 500 \text{ g} - 150 \text{ g } \)

\(= 350\text{ g }\)

Mass of 1 apple 

\(= 350 \text{ g} \div 5 \)

\(= 70 \text{ g } \)

Answer:

\(70\text{ g }\)


 

Question 7: 

Look at the diagram below. 

What is the mass of object A?

 

  1. 200\( \text{ g }\)
  2. 400\( \text{ g }\)
  3. 700\( \text{ g }\)
  4. 1100\( \text{ g }\)

 

Solution: 

Mass of 2 Object A, Object B and Object C \(= 1100 \text{ g }\)

Mass of Object B and Object C \(= 700 \text{ g }\)

Mass of 2 Objects A 

\(= 1100 \text{ g} - 700 \text{ g }\)

\(= 400 \text{ g }\)

 

Mass of Object A 

\(= 400 \text{ g} \div 2 \)

\(= 200 \text{ g } \)

Answer:

(1) \(200\text{ g }\)


 

Measuring Volume

To measure the volume of water, we usually use a beaker or a measuring cylinder.

To find the volume of water, we have to first find the value of each interval. From there, we will be able to determine the volume of water by looking at the water level. 


 

Question 1: 

Look at the diagram below. 

The volume of the water in the beaker is __________.

 

Solution:  

Volume represented by 5 intervals \(= 1000 \text{ mℓ }\)
Volume represented by 1 interval \(\begin{align}\\[2ex] &= 1000 \text{ mℓ} \div 5 \\[2ex] &= 200 \text{ mℓ} \end{align}\)
                                       3rd interval\(\begin{align}\\[2ex] &= 3 \times 200\text{ mℓ}  \\[2ex] &= 600 \text{ mℓ} \end{align}\)

Answer:

\(600 \text{ mℓ }\)


 

Question 2: 

Look at the diagram below.

What is the volume of the water in the beaker?

 

  1. 103\( \text{ mℓ }\)
  2. 130\( \text{ mℓ }\)
  3. 133\( \text{ mℓ }\)
  4. 1300\( \text{ mℓ }\)

 

Solution:  

Volume represented by 5 intervals \(= 50 \text{ mℓ }\)

 Volume represented by 1 interval 
\(\begin{align}\\[2ex] &= 50 \text{ mℓ} \div 5 \\[2ex] &= 10 \text{ mℓ} \end{align}\)
 

The volume of water in the beaker is 3 intervals after \(100 \text{ mℓ }\).

Volume of water in the beaker \(= 130 \text{ mℓ }\)

Answer:

(2) \(130\text{ mℓ }\)


 

Question 3: 

Look at the diagram below.

What is the volume of the water in the beaker?

 

  1. 250\( \text{ mℓ }\)
  2. 300\( \text{ mℓ }\)
  3. 450\( \text{ mℓ }\)
  4. 500\( \text{ mℓ }\)

 

Solution: 

Volume represented by 10 intervals \(= 600 \text{ mℓ }\)

Volume represented by 1 interval 

\(= 600 \text{ mℓ } \div 10 \\ = 60\text{ mℓ }\)
 

 Volume of water in the beaker
\(\begin{align}\\[2ex] &= 60 \text{ mℓ} \times 5\\[2ex] &= 300 \text{ mℓ } \end{align}\)

Answer:

(2) \(300\text{ mℓ }\)


 

Continue Learning
Volume Money
Mass Fractions
Addition And Subtraction Whole Numbers 1
Whole Numbers 3 Whole Numbers 6
Bar Graphs Angles
Multiplication And Division Length, Mass And Volume
Length Area And Perimeter
Parallel And Perpendicular Lines  

 

Resources - Academic Topics
icon expand icon collapse Primary
icon expand icon collapse Secondary
icon expand icon collapse
Book a free product demo
Suitable for primary & secondary
select dropdown icon
Our Education Consultants will get in touch with you to offer your child a complimentary Strength Analysis.
Book a free product demo
Suitable for primary & secondary
Claim your free demo today!
Claim your free demo today!
Arrow Down Arrow Down
Arrow Down Arrow Down
*By submitting your phone number, we have your permission to contact you regarding Geniebook. See our Privacy Policy.
Geniebook CTA Illustration Geniebook CTA Illustration
Turn your child's weaknesses into strengths
Geniebook CTA Illustration Geniebook CTA Illustration
Geniebook CTA Illustration
Turn your child's weaknesses into strengths
Get a free diagnostic report of your child’s strengths & weaknesses!
Arrow Down Arrow Down
Arrow Down Arrow Down
Error
Oops! Something went wrong.
Let’s refresh the page!
Error
Oops! Something went wrong.
Let’s refresh the page!
We got your request!
A consultant will be contacting you in the next few days to schedule a demo!
*By submitting your phone number, we have your permission to contact you regarding Geniebook. See our Privacy Policy.
Gain access to 300,000 questions aligned to MOE syllabus
Trusted by over 220,000 students.
Trusted by over 220,000 students.
Arrow Down Arrow Down
Arrow Down Arrow Down
Error
Oops! Something went wrong.
Let’s refresh the page!
Error
Oops! Something went wrong.
Let’s refresh the page!
We got your request!
A consultant will be contacting you in the next few days to schedule a demo!
*By submitting your phone number, we have your permission to contact you regarding Geniebook. See our Privacy Policy.
media logo
Geniebook CTA Illustration
Geniebook CTA Illustration
Geniebook CTA Illustration
Geniebook CTA Illustration Geniebook CTA Illustration
icon close
Default Wrong Input
Get instant access to
our educational content
Start practising and learning.
No Error
arrow down arrow down
No Error
*By submitting your phone number, we have
your permission to contact you regarding
Geniebook. See our Privacy Policy.
Success
Let’s get learning!
Download our educational
resources now.
icon close
Error
Error
Oops! Something went wrong.
Let’s refresh the page!