# Area And Perimeter 1

1. Finding the maximum number of squares that can be fitted/cut from a rectangle
2. Finding unknown dimensions given area of a rectangle/square
3. Finding unknown dimensions given perimeter of a rectangle/square

Let’s recap P3 Area and Perimeter first!

## Perimeter

The perimeter of a shape is the total distance around the shape.

### Perimeter Of A Square

 \begin{align} &= \text{Length + Length + Length + Length} \\[2ex] &= 4 \times \text{Length} \end{align}

### Perimeter Of A Rectangle

 $= \text{Length + Breadth + Length + Breadth}$

## Area

The area is the space occupied by the figure.

### Area Of A Square

 \begin{align} = \text{Length} \times \text{Length} \end{align}

### Area Of A Rectangle

 \begin{align} = \text{Length} \times \text{Breadth} \end{align}

Question 1:

Find the area and perimeter of the square below.

Solution:

Area of square

\begin{align} &= 6 \;cm \times 6 \;cm \\[2ex] &= 36 \;cm^2 \end{align}

Perimeter of square

\begin{align} &= 4 \times 6 \;cm \\[2ex] &= 24 \;cm \end{align}

Area: $36 \;cm^2$

Perimeter: $24 \;cm$

Question 2:

Find the area and perimeter of the rectangle below.

Solution:

Area of rectangle

\begin{align} &= 6 \;cm \times 4 \;cm \\[2ex] &= 24 \;cm^2 \end{align}

Perimeter of rectangle

\begin{align} &= 6 \;cm + 4 \;cm + 6 \;cm + 4 \;cm \\[2ex] &= 20 \;cm \end{align}

Area: $24 \;cm^2$

Perimeter: $20 \;cm$

## 1. Finding the maximum number of squares that can be     fitted / cut from a rectangle

To find the maximum number of squares that can be fitted/cut from an area, we will first find out the number of squares that are able to fit along the length and the breadth of that area.

Question 1:

What is the maximum number of $1 \;cm$ squares that can be cut from the rectangle?

Solution:

Number of $1 \;cm$ squares along the length of the rectangle

\begin{align} &= 5 \;cm ÷ 1 \;cm \\[2ex] &= 5 \end{align} ​

Number of $1 \;cm$ squares along the breadth of the rectangle

\begin{align} &= 3 \;cm ÷ 1 \;cm \\[2ex] &= 3 \end{align} ​

Maximum number of squares that can be cut from the rectangle

\begin{align} &= 5 \times 3 \\[2ex] &= 15 \end{align}

$15$ squares

Question 2:

What is the maximum number of $2 \;cm$ squares that can be cut from the rectangle?

Solution:

Number of $2 \;cm$ squares along the length of the rectangle

\begin{align} &= 8 \;cm \div 2 \;cm \\[2ex] &= 4 \end{align}

Number of $2 \;cm$ squares along the breadth of the rectangle

\begin{align} &= 6 \;cm \div 2 \;cm \\[2ex] &= 3 \end{align}

Maximum number of squares that can be cut from the rectangle

\begin{align} &= 4 \times 3 \\[2ex] &= 12 \end{align}

$12$ squares

Question 3:

What is the greatest number of 4-cm squares that can be cut from the rectangle?

Solution:

Number of $4 \;cm$ squares along the length of the rectangle

\begin{align} &= 16 \;cm \div 4\;cm \\[2ex] &= 4 \end{align}

Number of $4 \;cm$ squares along the breadth of the rectangle

\begin{align} &= 10 \;cm \div 4\;cm \\[2ex] &= 2\;R \;2\;cm \end{align}

We ignore the part which is represented by the remainder of $2\;cm$ as no squares can be cut from it.

Greatest number of squares that can be cut from the rectangle

\begin{align} &= 4 \times 2 \\[2ex] &= 8 \end{align}

$8$ squares

## 2. Finding unknown dimensions given area of a rectangle / square

$\text{Area Of A Rectangle} = \text{Length} \times \text{Breadth}$

Therefore,

\begin{align} \text{Length Of A Rectangle} &= \text{Area} \div \text{Breadth} \\[2ex] \text{Breadth Of A Rectangle} &= \text{Area} \div \text{Length} \end{align} ​

Question 1:

The area of a rectangle is $126 \;cm^2$. If its breadth is $7 \;cm$, what is the length of the rectangle?

Solution:

Length of the rectangle

\begin{align} &= 126 \;cm^2 ÷ 7 \;cm \\[2ex] &= 18 \;cm \end{align}

$18 \;cm$

Question 2:

The area of a rectangle is 72 cm2. Given that the length of the rectangle is 9 cm, find the breadth of the rectangle.

Solution:

\begin{align}​​ &= 72 \;cm^2 \div 9 \;cm\\[2ex] &= 8 \;cm \end{align}

$8 \;cm$

Question 3:

The area of a square is $64 \;cm^2$. Find the length of one side of the square.

Solution:

Since $8 \;cm \times 8 \;cm = 64 \;cm^2$,

Length of one side of each square $= 8 \;cm$

$8 \;cm$

Question 4:

The figure below is made up of $3$ identical squares. Given that the total area of the figure is $75 \;cm^2$, find the length of one side of each square.

Solution:

Area of 1 square

\begin{align}​​ &= 75 \;cm^2 \div 3\\[2ex] &= 25 \;cm^2 \end{align}

Since $5 \;cm \times 5 \;cm = 25 \;cm^2$,

Length of one side of each square $= 5 \;cm$

$5 \;cm$

## 3. Finding unknown dimensions given perimeter of a rectangle/square

\begin{align} \text{Perimeter Of Rectangle} &= \text{Length + Length + Breadth + Breadth}\\[2ex] \text{Length Of Rectangle} &= \text{(Perimeter - Breadth - Breadth) ÷ 2}\\[2ex] \text{Breadth Of Rectangle} &= \text{(Perimeter - Length - Length) ÷ 2} \end{align}

Question 1:

The perimeter of a rectangle is $36 \;cm$. Given that its breadth is $5 \;cm$, find its length.

Solution:

\begin{align}​​ \text{Perimeter of a rectangle} &= \text{Length + Breadth + Length + Breadth} \\[3ex] \text{Total length of 2 lengths} &= 36 \;cm - 5 \;cm - 5 \;cm \\[2ex] &= 26 \;cm\\[3ex] \text{Length of rectangle} &= 26 \;cm ÷ 2 \\[2ex] &= 13 \;cm \end{align}

$13 \;cm$

Question 2:

The perimeter of a rectangle is $72 \;cm$. Given that its length is $24 \;cm$, find its breadth.

Solution:

\begin{align}​​ \text{Perimeter of a rectangle} &= \text{Length + Breadth + Length + Breadth} \\[3ex] \text{Total length of 2 breadths} &= 72 \;cm - 24 \;cm - 24 \;cm \\[2ex] &= 24 \;cm\\[3ex] \text{ Breadth of rectangle} &= 24 \;cm ÷ 2 \\[2ex] &= 12 \;cm \end{align}

$12 \;cm$

​\begin{align} \text{Perimeter of a square} &= 4 \times \text{Length} \\[2ex] \text{Length of one side of a square} &= \text{Perimeter} \div 4 \end{align}

Question 3:

The perimeter of a square is $60 \;cm$. Find the length of one side of the square.

Solution:

Perimeter of a square $= 4 \;×$ Length
Length of one side of the square\begin{align}​​\\[2ex] &= 60 \;cm \div 4\\[2ex] &= 15 \;cm \end{align}

$15 \;cm$

Question 4:

The area of a rectangular garden is $168 \;m^2$. Its breadth is 8 m.

1. Find the length of the garden.
2. Vincent jogged round the entire rectangular garden twice. Find the distance he jogged.

Solution:

1. Length of the rectangle\begin{align}​​\\[2ex] &= 168 \;m^2 \div 8 \;m \\[2ex] &= 21 \;m \end{align}
2. Perimeter of garden\begin{align}​​\\[2ex] &= 21 \;m + 8 \;m + 21 \;m + 8 \;m \\[2ex] &= 58 \;m \end{align}
Distance he jogged \begin{align}​​\\[2ex] &= 58 \;m \times 2\\[2ex] &= 116 \;m \end{align}

1. $21 \;m$

1. $116 \;m$

Question 5:

Elaine jogged $36 \;m$ round a square sand pit.

1. Find the length of one side of the sand pit.
2. Find the area of the square sand pit.

Solution:

1. Length of one side of the sand pit\begin{align}​​\\[2ex] &= 36 \;m \div 4\\[2ex] &= 9 \;m \end{align}
2. Area of the sand pit\begin{align}​​\\[2ex] &= 9 \;m \times 9 \;m\\[2ex] &= 81 \;m^2 \end{align}

1. $9 \;m$

1. $81 \;m^2$

Continue Learning
Multiplication Whole Numbers
Multiplication And Division Decimals
Model Drawing Strategy Division
Fractions Factors And Multiples
Area And Perimeter 1 Line Graphs
Time

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